Question 190818
The area of a triangle is 96 sq. inches. Its altitude is 2 inches greater than five times its base. Find the altitude. ( A= 1/2bh ) 
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Let b = base
then
5b-2 = altitude or height
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therefore applying:
A= 1/2bh
we have
96 = (1/2)b(5b-2)
96 = (1/2)b(5b-2)
192 = b(5b-2)
192 = 5b^2 - 2b
0 = 5b^2 - 2b - 192
Apply the quadratic equation to solve for b (details below):
b = {6.464, -6.064}
We can toss out the negative solution so we get:
b = 6.464 inches (base)
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To find the height or altitude:
5b-2 = 5(6.464)-2 =  30.32 inches (altitude)
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Details of quadratic equation below:
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*[invoke quadratic "b", 5, -2, -196 ]