Question 190815
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Given: x-2y=6 


Via Slope-Intercept Form,{{{system(y=mx+b)}}}


{{{x-6=2y}}} ---> {{{2y=x-6}}}
Divide by 2 both terms:
{{{cross(2)y/cross(2)=(x-6)/2=(1/2)x-6/2=(1/2)x-3}}}
{{{red(y=(1/2)x-3)}}}


Let Fy=0: 
Going back to given eqn:
x-2(0)=6
{{{highlight(x=6)}}}, X-Intercept


Let Fx=0:
{{{0-2(y)=6}}}, divide both terms by -2:
{{{cross(-2)y/cross(-2)=cross(6)3/cross(-2)1}}}
{{{y=3/-1=highlight(-3)}}}, Y-Intercept



Let's see the graph:
{{{drawing(400,400,-9,9,-9,9,graph(400,400,-9,9,-9,9,(1/2)x-3),blue(circle(0,-3,.15)),blue(circle(6,0,.15)))}}}


Thank you,
Jojo</font>