Question 190778
Note: 430 g = 0.430 kg (the standard mass unit is a kilogram)


First, recall that Newton's Second Law is:


{{{F=ma}}} where "F" is the force applied to the object, "m" is the mass of the object, and "a" is the acceleration that the the object undergoes.



Since "A 430-g soccer ball lying on the ground is kicked with a force of 800 N", this means that {{{m=0.430}}} (see note above) and {{{F=800}}}



So the equation then becomes {{{800=0.430a}}} and solving for "a" gets us {{{a=800/0.430=1860.4651}}}



So the acceleration is roughly {{{a=1860.4651}}} meters per second squared.



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Now recall that one of the many kinematics equations is 


{{{v=v[0]+at}}} where "v" is the final velocity, {{{v[0]}}} is the initial velocity, "a" is the acceleration, and "t" is the time the force is applied



So because the initial velocity is 0, this means that {{{v[0]=0}}}.  Since "the kick lasts 0.01s", this means that {{{t=0.01}}}



{{{v=v[0]+at}}} Start with the given kinematics equation.



{{{v=0+1860.4651(0.01)}}} Plug in {{{v[0]=0}}}, {{{a=1860.4651}}}, and {{{t=0.01}}}



{{{v=1860.4651(0.01)}}} Simplify



{{{v=18.604651}}} Multiply



{{{v=18.6}}} Round to the nearest tenth



So the ball flies off at a speed of about 18.6 m/s