Question 190622
Note: since sine is an odd function, this means that {{{sin(-x)=-sin(x)}}}. So {{{sin(-pi/3)=-sin(pi/3)}}}



In order to evaluate {{{-sin(pi/3)}}}, just evaluate {{{sin(pi/3)}}} and negate it.



Looking at the unit circle:


<img src="http://www.math.ucsd.edu/%7Ejarmel/math4c/Unit_Circle_Angles.png">



We see that at the theta value {{{pi/3}}}, the y-coordinate of the point on the unit circle is {{{y=sqrt(3)/2}}}



So this simply means that {{{sin(pi/3)=sqrt(3)/2}}}



Now negate to get {{{-sin(pi/3)=-sqrt(3)/2}}}



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Answer:



So {{{sin(-pi/3)=-sqrt(3)/2}}}