Question 190592
Take note that the denominators are {{{2x+5}}} and {{{x^2}}}. Usually (not always), the LCD is simply the product of all the denominators. So just multiply {{{2x+5}}} and {{{x^2}}} to get {{{(2x+5)x^2}}}. Now just factor {{{x^2}}} to get {{{(x)(x)}}}. So the LCD becomes  {{{(2x+5)(x)(x)}}}. So the answer is C



Note: you might see the LCD as {{{x^2(2x+5)}}} or {{{(x)(x)(2x+5)}}} (the factors are just rearranged)