Question 190594
It turns out that ANY number of the form {{{a+bi}}} added to it's complex conjugate of the form {{{a-bi}}} is 



{{{(a+bi)+(a-bi)=(a+a)+(bi-bi)=2a+0i=2a}}}



So adding ANY complex number to it's complex conjugate results in a real number.



Example:


Let's pick the number {{{2+3i}}} (where a = 2 and b = 3) and add it to it's complex conjugate {{{2-3i}}} to get



{{{(2+3i)+(2-3i)=(2+2)+(3i-3i)=4+0i=4}}}



In short {{{(2+3i)+(2-3i)=4}}}



Note: it turns out that multiplying a complex number by it's complex conjugate also results in a real number (division is a different story however).