Question 190525
{{{2/(x-6)+4x}}} Start with the given expression



Take note that the LCD is {{{x-6}}}



{{{2/(x-6)+(4x(x-6))/(x-6)}}} Multiply the second term by {{{(x-6)/(x-6)}}} to get the denominator equal to the LCD



{{{2/(x-6)+(4x^2-24x)/(x-6)}}} Distribute



{{{(2+4x^2-24x)/(x-6)}}} Combine the fractions



{{{(4x^2-24x+2)/(x-6)}}} Rearrange the terms




So {{{2/(x-6)+4x=(4x^2-24x+2)/(x-6)}}} where {{{x<>6}}}