<PRE><B>Question 190486</B>
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If it is an isosceles right triangle, then &lt;i&gt;&lt;b&gt;both&lt;/b&gt;&lt;/i&gt; of the legs are the same length, namely &lt;i&gt;&lt;b&gt;a&lt;/b&gt;&lt;/i&gt;, because of the definition of isosceles.


Pythagoras&#39; Theorem says:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  c = sqrt{a^2 + b^2}]


But for this triangle, *[tex \LARGE  b = a] so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  c = sqrt{a^2 + a^2} = sqrt{2a^2} = a sqrt{2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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