Question 190473
<font face="Garamond" size="+2">

There are 26 alphabetic characters A - Z and 10 numbers, 0 - 9.


Since you cannot use zero for the first digit, there are 26 + 9 = 35 ways to choose the first digit.


The second, third, and fourth digits can be anything, so there are 26 + 10 = 36 ways to choose each of those.


And the fifth and sixth position can only be alphabetic, so you only have 26 ways to choose each of the last two digits.


So for each of the 35 ways to choose the first digit, there are 36 ways to choose the second digit, so 35 X 36 = 1260 ways to choose the first two digits.  For each of those ways there are 36 ways to choose the third digit...and so on, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  35 \times 36 \times 36 \times 36 \times 26 \times 26]


You can operate a calculator as well as I can.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>