Question 190482
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Use the rule:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  sqrt{\frac{a}{b}}=\frac{sqrt{a}}{sqrt{b}}]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  sqrt{\frac{9}{25}}\ =\ \frac{sqrt{9}}{sqrt{25}}\ =\ \frac{3}{5} ]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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