Question 190404
Remember, the distributive property states that {{{a(b+c)=ab+ac}}}. This can be reversed to get {{{ab+ac=a(b+c)}}}. In other words, we've factored out the common term "a".



In the case of {{{ c^2-7c=0 }}}, the term {{{c^2}}} can be factored to get {{{ c*c-7c=0 }}}


Notice how there's a common factor of "c". So factor this out to get {{{c(c-7)=0}}}



Now set each term equal to zero and solve each equation.