Question 190403
<font face="Garamond" size="+2">


Each term is *[tex \LARGE 1 + 4(i - 1)\ =\ 1 + 4i - 4\ =\ 4i - 3] so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \sum_{i=1}^{5}(4i - 3)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>