Question 190403
Notice how we're adding 4 to each term to get the next term. So this means that the sequence is arithmetic. Since the series starts at 1, this means that the nth term of the sequence is *[Tex \LARGE a_{n}=4n+1] where "n" starts at 0



So the series is simply


*[Tex \LARGE \displaystyle \sum_{i=0}^4 4i+1]



This means that *[Tex \LARGE \displaystyle \sum_{i=0}^4 4i+1 = 1+5+9+13+17]