Question 190383
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First condition,

<font color=blue>(100%)(AF) + (20%)(10qts) = (50%)(S) </font>-----> Eqn 1


Also we know, <font color=blue> AF + 10 qts = S </font> ------> Eqn 2



Substitute Eqn 2 in Eqn 1:


{{{(1)(AF)+(0.20)(10)=(0.50)(AF+10)}}}
{{{AF+2=0.50(AF)+5}}}
{{{AF-0.50(AF)=5-2}}}
{{{0.50(AF)=3}}} ----> {{{cross(0.50)AF/cross(0.50)=cross(3)6/cross(0.50)}}}
<font color=blue>AF = 6 qts </font>, amount of 100% AF needed



We get the total Solution, (via Eqn 2):
{{{S=6+10}}}
{{{red(S=16qts)}}}



Let us check,
{{{(1)(6)+0.20(10)=0.50(16)}}}
{{{6+2=8qts}}}
{{{8qts=8qts}}}



Thank you,
Jojo</font>