Question 190309
Left side:
m/(1+i); multiply numerator and denominator by (1-i) and we get:
m(1-i)/(1+1)=m(1-i)/2
Now we have:
m(1-i)/2=1-ni  multiply each side by 2
m-mi=2-2ni add mi and also ni to each side
m-mi+mi+ni=2-2ni+ni+mi  collect like terms
m+ni=2-ni+mi=2-i(n-m)

Hope this helps---ptaylor