Question 190265
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{{{0 = 2x(x^2+1)^(-1/2) - 1}}}
{{{0 = 2x/(x^2+1)^(1/2) - 1}}}
Now, multiply both sides by {{{(x^2+1)^(1/2)}}}
{{{0 = 2x - (x^2+1)^(1/2)}}}
{{{(x^2+1)^(1/2) = 2x}}}
Squaring both sides:
{{{x^2+1 = 4x^2}}}
Moving all terms to the right:
{{{0 = 4x^2 - x^2 - 1}}}
Solving with the quadratic equation yields:
x = {0.6404, -0.3904}
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Details of quadratic follows:
*[invoke quadratic "x", 4, -1, -1 ]