<PRE><B>Question 190165</B>
    a cylinder with a radius of 6 inches and a height of 8 inches has its radius quadrupled. How many times greater is the volume of the larger cylinder than the smaller cylinder?
.
Smaller cylinder:
radius = 6 inches
height = 8 inches
area = (pi)r^2h
area = (3.14)6^2(8)
.
Larger cylinder:
radius = 24 inches
height = 8 inches
area = (pi)r^2h
area = (3.14)24^2(8)
.
[(3.14)6^2(8)] / [(3.14)24^2(8)]
[6^2(8)] / [24^2(8)]
[6^2] / [24^2]
[36] / [576]
16 times greater
</PRE>