<PRE><B>Question 190018</B>
And suppose that the games form independent trials where in each game played the probability that A wins is 0.36 and the probability that B wins is 0.64. 
What is the probablity one of the teams wins the first 3 games but the other team wins the series? 
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Prob A wins after three losses:
(0.64)^3*(0.36)^4 = 0.0044
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Prob B wins after three losses:
(0.36)^3*0.64^4 = 0.00783
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Cheers,
Stan H.</PRE>