Question 190082
Solve for d:
{{{6d^2+21d = 10d+35}}} First, get the equation into standard quadratic form:{{{ax^2+bx+c = 0}}} Subtact 10 d from both sides.
{{{6d^2+11d = 35}}} Now subtract 35 from both sides.
{{{6d^2+11d-35 = 0}}} Now factor the trinomial.
{{{(3d-5)(2d+7) = 0}}} Apply the zero product rule.
{{{3d-5 = 0}}} or {{{2d+7 = 0}}} so that...
{{{3d = 5}}} and {{{highlight(d = 5/3)}}} or
{{{2d = -7}}} and {{{highlight(d = -7/2)}}}