Question 190087
any line parallel to 7x=3y+5 will have the same slope.....so the first step is to find the slope of this line  3y=7x-5---->y=(7/3)x-5/3.......so the slope is 7/3
:
Now using the point slope formula with (-7,4) as our point
:
y-4=(7/3)(x+7)
:
y-4=7/3x+49/3
:
3y-12=7x+49.........multiplied all terms by 3
:
7x+3y=61