Question 189962
Find a third degree polynomial function such that
f(0)=3 and whose zeros are 1, 2, and 3.
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f(x) = a(x-1)(x-2)(x-3)
f(0) = a(-1)(-2)(-3) = 3
-6a = 3
a = -1/2
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3rd degree polynomial:
f(x) = (-1/2)(x-1)(x-2)(x-3)
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That polynomial satisfies the conditions.
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Cheers,
Stan H.