Question 189891
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I'm not sure I understand what you mean by 'both parts of the hypotenuse.'


From your description of the diagram, 11 must be the entire length of the hypotenuse, so you can ignore the altitude measurement and just use the hypotenuse and one leg:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  b = sqrt{11^2 - 5^2} = sqrt{121 - 25} = sqrt{96} = 4 sqrt{6}]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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