<PRE><B>Question 189879</B>
*[Tex \LARGE \left(-64\right)^{\frac{2}{3}}] ... Start with the given expression.



{{{(root(3,-64))^2}}} Convert to radical notation



{{{(root(3,(-4)^3))^2}}} Rewrite {{{-64}}} as {{{(-4)^3}}}



{{{(-4)^2}}} Take the cube root of {{{(-4)^3}}} to get -4



{{{16}}} Square -4 to get 16



So *[Tex \LARGE \left(-64\right)^{\frac{2}{3}}=16] 
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