Question 189829
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Let <i>x</i> be your age now.  Then <i>x</i> + 7 is your age 7 years from now and <i>x</i> - 1 is your age one year ago.  Twice as old as you were one year ago is 2(<i>x</i> - 1).  So:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x + 7 = 2(x - 1)]


Solve for <i>x</i> to get your answer.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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