Question 189754
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Let's deal with the 1st part of the eqn:
{{{highlight(3/5 = (y+1)/20) = 18/m }}}
cross multiply,
{{{y+1=(3/5)(20)=60/5=12}}}
{{{y=12-1}}}
{{{highlight(y=11)}}}


Next part of the eqn:
{{{highlight(3/5) = (y+1)/20 = highlight(18/m)}}}
{{{3/5=18/m}}}, cross multiply
{{{3m=18*5=90}}} ----> {{{cross(3)m/cross(3)=cross(90)30/cross(3)}}}
{{{highlight(m=30)}}}


Let us check by susbtituting values to our eqn:
{{{3/5 = (y+1)/20 = 18/m }}}
{{{3/5=(highlight(11)+1)/20=18/highlight(30)}}}
{{{3/5=12/20=18/30}}}{{{system(3/5=red(a),12/20=red(b),18/30=red(c))}}}


Divide {{{red(b)}}} both by 4, and {{{red(c)}}} by 6 to reduce:
{{{3/5=cross(12)3/cross(20)5=cross(18)3/cross(30)5}}}
{{{3/5=3/5=3/5}}}


Thank you,
Jojo</font>