Question 189638
<font face="Tahoma" size=1.5>
</pre><font size=4><b>
Let us state the given:


Hypotenuse = <font color=blue>c = 10 feet</font>
Longer Leg = <font color=blue>a = a </font>
Shorter Leg = <font color=blue>b =  2a-10 </font> 


Going to our Pyth.Theorem:
{{{c^2=a^2+b^2}}}
{{{10^2=a^2+(2a-10)^2}}}
{{{10^2=a^2+(2a-10)^2}}}
{{{100=a^2+4a^2-40a+100}}}
{{{5a^2-40a+cross(100)-cross(100)=0}}}
{{{5a*highlight((a-8))=0}}}
{{{a=8ft)}}}, Longer Leg


{{{b=2a-10=2*8-10=16-10=red(6ft)}}}, Shorter Leg (answer)


Let's check:
{{{c^2=a^2+b^2}}}
{{{10^2=8^2+6^2}}}
{{{100=64+36}}}
{{{100ft=100ft}}}
Thank you,
Jojo</font>