Question 189724
For what positive number(s) is the sum of the number and its reciprocal the smallest? 
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Let the number be "s".
Equation:
sum = s + 1/s 
S = s + 1/s
Sx = s^2 + 1
s^2 - sS +1 = 0
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mimimum occurs when s = -b/2a
Your problem:
s = S / 2
1/s = 2/S
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Answer: The number is (1/2)Sum
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Cheers,
Stan H.