Question 189628
Let x=a positive even integer
x+2=next even integer

{{{x*(x+2)=x+(x+2)+142}}}
{{{x^2+2x=2x+2+142}}}

Subtracting 2x from both sides we get:

{{{x^2=144}}}

Taking the square root of both sides, we get:

x=12 and/or x=-12

Since we're only looking for positive integers we take x=12,

x+2=12+2=14

So the 2 consecutive even integers are 12 and 14.