Question 189610
{{{x^4-5x^2-24=0}}}
Notice that x^4 = (x^2)^2
.
{{{(x^2-8)(x^2+3)=0}}}
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Setting each expression in parentheses equal to zero and solve for x:
(x^2-8)=0
x^2 = 8
x = +- sqrt(8)
x = +- 2sqrt(2)
.
(x^2+3)=0
x^2 = -3
x = +- sqrt(-3)
x = +- sqrt(3)i