Question 189549
Simplify:
{{{(25-b^2)/(b^2+12b+35)}}} Rewrite the numerator as a negative binomial:
{{{(-(b^2-25))/(b^2+12b+35)}}} Now factor both the numerator and the denominator.
{{{-(b-5)cross((b+5))/((b+7)cross((b+5)))}}} Finally, cancel the indicated factors.
{{{highlight(-(b-5)/(b+7))}}}