Question 189549


{{{(25-b^2)/(b^2+12b+35)}}} Start with the given expression.



{{{(-(b-5)(b+5))/(b^2+12b+35)}}} Factor {{{25-b^2}}} to get {{{-(b-5)(b+5)}}}.



{{{(-(b-5)(b+5))/((b+7)(b+5))}}} Factor {{{b^2+12b+35}}} to get {{{(b+7)(b+5)}}}.



{{{-((b-5)highlight((b+5)))/((b+7)highlight((b+5)))}}} Highlight the common terms. 



{{{-((b-5)cross((b+5)))/((b+7)cross((b+5)))}}} Cancel out the common terms. 



{{{-(b-5)/(b+7)}}} Simplify. 



So {{{(25-b^2)/(b^2+12b+35)}}} simplifies to {{{-(b-5)/(b+7)}}}.



In other words, {{{(25-b^2)/(b^2+12b+35)=-(b-5)/(b+7)}}} where {{{b<>-7}}} or {{{b<>-5}}}