Question 189531
{{{ log5 (4x-1) >= log5 (x+2) }}}
Anti-log5 of both sides produces:
{{{ (4x-1) >= (x+2) }}}
{{{ 4x-1 >= x+2 }}}
{{{ 3x-1 >= 2 }}}
{{{ 3x >= 3 }}}
{{{ x >= 1 }}}