Question 189528
log_16 (n) = -1/2 becomes 16^(-1/2) = n.

You need to apply the log rules to these problems or else logs will not make sense.

16 to the -1/2 is the same thing as 1/16^(1/2).  Here I applied the rules for negative exponents.

1/16^(1/2) = 1/(square root of 16) and this is equated to n.

Final answer: 1/4 = n