Question 189508
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Let <i>x</i> be the number of $5 coins.  Then the number of 20 cent coins must be 4<i>x</i>.


When I do coin problems, I usually convert dollars and cents to just cents.  Here, the total amount of money is 1740 cents, the $5 coins are worth 500 cents each, and the 20 cent coins are worth 20 cents each.


Since we have the quantity <i>x</i> of 500 cent coins, the total value of these coins must be 500<i>x</i> cents.  Likewise, the total value of the 20 cent coins must be 20 X 4<i>x</i> or 80<i>x</i> cents.


Adding these two values together must give the total amount of money, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  500x + 80x = 1740]


Solve for <i>x</i> to learn the number of $5 coins, and multiply that by 4 to get the number of 20 cent coins.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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