Question 189482
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Given Line Eqn ---- > <font color=blue>2x + y =-11</font>


We know a line passes thru the x & y axis called the intercepts.


For x -Intercept, let fy=0:
{{{2x+0=-11}}}
{{{cross(2)x/cross(2)=-11/2}}}
{{{red(x=-11/2)}}}


For y-Intercept, let fx=0:
{{{2(0)+y=-11}}}
{{{red(y=-11)}}}


Then following our Slope-Intercept Form, <font color=blue>y=mx+b</font>
2x+y=-11 -----> y= -2x-11, 
where {{{m=Slope=DELTA(y)/DELTA(x)=(y[2]-y[1])/(x[2]-x[1])=-2/1)}}}
Also, y-Intercept,{{{b=-11}}}



As we see the graph,
{{{drawing(400,400,-8,4,-15,8,graph(400,400,-8,4,-15,8,-2x-11),blue(circle(-11/2,0,.10)),blue(circle(0,-11,.10)))}}}


As we would see the Slope in <font color=green>green points</font>, a movememnt of <font color=blue>-2</font> on the y-axis (from the y-Intercept) 
and <font color=blue>+1</font> on the x-axis.


Starting point (0,-11):
On x -axis,{{{0+red(1)=1}}}
On y-axis, {{{-11+red(-2)=-13}}}
Next point, <font color=blue>(1,-13)</font>


Again, on point (0,-11):
On x-axis, {{{0-red(1)=-1}}}
on y-axis, {{{-11-red(-2)=-11+2=-9}}}
Next point, <font color=blue>(-1,-9)</font>


Next, on point (-1,-9):
On x-axis, {{{-1-red(+1)=-2}}}
On Y-axis, {{{-9-red(-2)=-9+2=-7}}}
Next point, <font color=blue>(-2,-7)</font>


....Just continue on the succeeding points.



{{{drawing(400,400,-8,4,-15,8,grid(1),graph(400,400,-8,4,-15,8,-2x-11),blue(circle(-11/2,0,.10)),blue(circle(0,-11,.10)),green(circle(1,-13,.03)),green(circle(-1,-9,.03)),green(circle(-2,-7,.03)),green(circle(1,-13,.10)),green(circle(-1,-9,.10)),green(circle(-2,-7,.10)))}}}



Thank you,
Jojo</font>