Question 189433
This is right:
{{{(2/3) - n*(5/8) = 7/12}}}
{{{3}}}, {{{8}}}, and {{{12}}} all go into {{{24}}} evenly, so
multiply both sides by {{{24}}}
{{{24*((2/3) - n*(5/8)) = 24*(7/12)}}}
{{{24*(2/3) - 24n*(5/8) = 14}}}
{{{16 - 15n = 14}}}
{{{-15n = -2}}}
{{{n = 2/15}}}
check answer:
{{{(2/3) - n*(5/8) = 7/12}}}
{{{(2/3) - (2/15)*(5/8) = 7/12}}}
{{{(2/3) - (1/12) = 7/12}}}
{{{(8/12) - (1/12) = 7/12}}}
{{{7/12 = 7/12}}}
OK