<PRE><B>Question 26212</B>
Let the 2nd side of the triangle = X
Then first side = 2X+8
And third side = 3X
Perimeter of a triangle is the sum of all its sides
i.e. X+2X + 8 + 3x = 6X+8
But we know this equals 128
i.e. 6x+8 = 128
Subtracting 8 on both sides
6X = 120
Dividing by 6 throughout
X = 20 which is the 2nd side
First side = 2X+ 8 = 2(20)+8 = 48
3rd side = 3X = 3(20) = 60</PRE>