Question 189369
{{{(s^4/t^6)^-4}}}
{{{(s^4)^(-4) / (t^6)^(-4)}}}
{{{s^(-16) / t^(-24)}}}
The rule is {{{s^(-a) = 1/s^a}}}, but you can do this, too:
{{{(s^16 / t^24)(t^24/s^16)(s^(-16) / t^(-24))}}}
Notice that the 1st 2 factors are just {{{1}}}
Now rearrange
{{{(s^16 / t^24)(s^(-16) / t^(-24))(t^24/s^16)}}}
{{{(s^(16-16)/t^(24-24))(t^24/s^16)}}}
{{{(s^0 / t^0)(t^24/s^16)}}}
{{{t^24/s^16}}} answer