Question 26265
Functions are truly easy things to use...


Given g(x) = {{{x^2 + 4x}}}


this says... given the "number" x in the g(x) definition, we alter it as defined by {{{x^2 + 4x}}}.


So, g(2) is {{{(2)^2 + 4(2)}}}
--> g(2) is 4 + 8
--> g(2) = 12


and g(-2) is {{{(-2)^2 + 4(-2)}}}
--> g(-2) = 4 - 8
--> g(-2) = -4


Can you see how simple it is?


jon.