Question 189254
{{{((x^2-4))/((x+3))}}} * {{{((x^2 + 4x + 3))/((2x - 4))}}}
:
Factor just like you did:
{{{((x-2)(x+2))/((x+3))}}} * {{{((x+3)(x+1))/((2x - 4))}}}
But you can also do this
{{{((x-2)(x+2))/((x+3))}}} * {{{((x+3)(x+1))/(2(x - 2))}}}
Cancel our (x-2) and (x+3) leaving:
(x+2) * {{{((x+1))/2}}} = {{{((x^2+3x+2))/2}}}