Question 189180
If your equation has the form
{{{f(x) = (x - z[1])(x - z[2])(x - z[3])}}} etc.
then {{{z[1]}}},{{{z[2]}}},{{{z[3]}}} etc. are the zeroes
The multiplicity is the number of times a zero is repeated,
for instance:
{{{f(x) = (x - z[1])^3(x - z[2])(x - z[3])}}}etc.
Zero {{{z[1]}}} has a multiplicity of {{{3}}}, since it's
repeated {{{3}}} times
In your equation:
{{{f(x) = (x^2-9)^2}}}, I can factor it some more:
{{{f(x) = ((x + 3)(x - 3))^2}}}
{{{f(x) = (x + 3)(x + 3)(x - 3)(x - 3)}}}
{{{f(x) = (x + 3)^2(x - 3)^2}}}
The zeroes are {{{x = -3}}} multiplicity of {{{2}}}
and {{{x = 3}}} multiplicity of {{{2}}} also