Question 189149
sqrt(5-x)=x-3
5-x=x^2-6x+9 square each side.
x^2-5x+4=0 subtract the left side from the right.
(x-4)(x-1)=0 factor
x=4, x=1 These are the proposed solutions. Now you have to put them into the original equation and check to see if the solution is a true one or if it is extraneous.
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sqrt(5-4)=4-3
sqrt(1)=1 true
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sqrt(5-1)=1-3
2=-2 extraneous
.
Ed