Question 189127
for each geometric series, find the sum. if the series has no sum, say so
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 24+12+6+3+...
a(1) = 24
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r = 12/24 = 1/2
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S(n) = a[1-r^n]/[1-r]
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Limit as n goes to infinity : S(n) = a/(1-r)
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Your problem:
Sum = 24/(1-(1/2)) = 24/(1/2) = 48
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Cheers,
Stan H.