Question 189110
Sometimes I do it this way:
{{{y = mx + b}}}
{{{m = -(5/8)}}}
The point (3,2) is given, so
{{{2 = -(5/8)*3 + b}}}
{{{2*8 = -15 + 8b}}}
{{{8b = 16 + 15}}}
{{{b = 31/8}}}
So the equation is:
{{{F(x) = -(5/8)*x + 31/8}}}
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The other way is:
{{{y - y[1] = m*(x - x[1])}}}
{{{y - 2 = -5/8*(x - 3)}}}
{{{y = -(5/8)*x + 15/8 + 2}}}
{{{y = -(5/8)*x + 15/8 + 16/8}}}
{{{y = -(5/8)*x + 31/8}}}
And, of course, {{{y = F(x)}}}