Question 189084
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Let <i>w</i> be the width and <i>l</i> be the length.


We know that the area of a rectangle is the length times the width, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A = lw]


But for this particular rectangle we are given that the length is 3 inches more than the width, so we can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  l = w + 3]


Now we can substitute this expression for the length into the area formula in place of <i>l</i> to create an area function of width:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  A(w) = (w+3)w = w^2 + 3w]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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