Question 188997
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If one revolution takes 30 seconds, then the wheel is moving at


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac {2 \pi}{30} ] radians per second.


If the diameter of the wheel is 40 meters, then its radius is 20 meters and a point on the outside of the wheel is changing height at a rate of


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  20 \cos\left(\frac {2 \pi}{30}\right)]


meters per second <i><b>relative to the centre of the circle</b></i>, so the height function with respect to time is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t) = 21 - 20 \cos\left(\frac {2 \pi}{30}t\right)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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