Question 188984
{{{(5x^3y^4)^2}}} Start with the given expression.



{{{(5^1x^3y^4)^2}}} Rewrite {{{5}}} as {{{5^1}}}



{{{5^(1*2)x^(3*2)y^(4*2)}}} Multiply the outer exponent by EVERY exponent in the parenthesis.



{{{5^2x^6y^8}}} Multiply



{{{25x^6y^8}}} Square 5 to get 25



So {{{(5x^3y^4)^2=25x^6y^8}}}