Question 188901
x^4 + x^2y^2 + y^4 
Using the quadratic equation:{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}} we get.
x=(-1+-sqrt[1^2-4*1*1])/2*1
x=(-1+-sqrt1-4)/2
x=(-1+-sqrt-3)/2
x=(-1+-1.732i)/2
x=1/2+-.866i
x=.5+-.866i ans.