Question 188940
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Given: {{{system(y=highlight(-2)x+7(EQN1),y=highlight(-2)x-6(EQN2))}}}


Just by looking on the eqns, they are <font color=blue>parallel</font>.


Why? Remember Parallel Lines have the same Slope=m, ---> y=mx+b


We can prove by solving the eqns.


In EQN 1:
Let fy=0 ----> {{{0=-2x+7}}} ----> {{{2x=7}}} ----> {{{cross(2)x/cross(2)=7/2}}}
{{{red(x=7/2)}}}, X-Intercept
Let fx=0 ----> {{{y=-2(0)+7}}}
{{{red(y=7)}}}, Y-Intercept


In EQN 2:
Let fy=0 ---> {{{0=-2x-6}}} ---> {{{2x=-6}}} ----> {{{cross(2)x/cross(2)=cross(-6)3/cross(2)}}}
{{{red(x=-3)}}}, X-Intercept
Let fx=0 ---> {{{y=-2(0)-6}}} 
{{{red(y=-6)}}}


We'll see the graph,
{{{drawing(400,400,-10,10,-10,10,graph(400,400,-10,10,-10,10,-2x+7,-2x-6),green(circle(7/2,0,.15)),green(circle(0,7,.15)),blue(circle(-3,0,.15)),blue(circle(0,-6,.15)))}}} --->  <font color=red>RED, EQN 1</font>; <font color=green>GREEN, EQN 2</font>


Thank you,
Jojo</font>