Question 188936
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Given: 3x + 2y =-6


Following Slope-Intercept Form, y=mx+b


{{{2y=-6-3x}}} 
{{{cross(2)y/cross(2)=(-6-3x)/2=(-6/2)-(3/2)x}}}
{{{red(y=(-3/2)x-3)}}}


Let fy=0 ( based on the given eqn)
{{{3x+2(0)=-6}}} 
{{{cross(3)x/cross(3)=cross(-6)2/cross(3)}}}
{{{red(x=-2)}}}, X-intercept


Let fx=0
{{{y=(-3/2)(0)-3=red(-3)}}}, Y-intercept


Let's see below
{{{drawing(400,400,-5,5,-5,5,graph(400,400,-5,5,-5,5,(-3/2)x-3),blue(circle(0,-3,.08)),blue(circle(-2,0,.08)))}}}


Thank you,
Jojo</font>